Pty Ltd. 1 -1 ?2 3??2 y= -sinx, x [0, ] ??2 2 ?解: (1)x y 例1.作出的图象。 y= -sinx, x [0, ] ??2 x y=sinx y=-sinx 0 00 1 -1 00 -11 00 2 π2 3π?2 π.. ... [0,2 π]x sinx, y?? Evaluation only. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Copyright 2004-2011 Aspose Pty Ltd. x yo -1 1 2 ?2?.... . [0,2 π]x sinx, y??[0,2 π]x sinx, y???1 x 001 12 01 -10 01 2 ππ2 3π sinx sinx 1?2 π2 3π例2.画出 y=1+sinx , x ∈[0, ]的简图?2?2 Evaluation only. Evaluation only. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Created with Aspose.Slides for .NET 3.5 Client Profile 5.2.0.0. Copyright 2004-2011 Aspose Pty Ltd. Copyright 2004-2011 Aspose Pty Ltd.
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