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地震灾后物资分配模型(数学建模)范文4

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0.0433РB3-PР(0.375,0.375,0.125,0.12)TР4Р0Р0.9Р0Р 由表可见,所有4个层次单排序的CR的值均小于0.1,符合满意一致性要求。Р层次总排序Р已知第二层(B层)相对于总目标A的排序向量分别为РW(2)=(0.4956,0.2319,0.0848,0.1374,0.0503)TР而第三层(p层)以第二层第i个因素Bi为准则时的排序向量分别为РP(3)1=(0.4956,0.2319,0.0848,0.1374,0.0503)TРP(3)2=(0,0.0553,0.5650,0.1175,0.2622)TРP(3)3=(0.375,0.375,0.125,0.125,0)TР则第三层(p层)相对于总目标的排序向量为РW=(P(3)1,P(3)2,P(3)3)*W(2)Р =(0.1488,0.1564,0.4011,0.1215,0.1723)TР层次总排序的一致性检验Р由于РCI(2)=(CI(2)1,CI(2)2,CI(2)3)=(0.0198,0.0389,0),РRI(2)=(RI(2)1,RI(2)2,RI(2)3)=(1.12,0.9,0.9)Р因此РCI(3)=C*I(2)*W(2)Р=(0.0198,0.0398,0)(0.1047,0.6370,0.2582)T=0.0269,РRI(3)=RI(2)*W(2)Р=(1.12,0.9,0.9)(0.1047,0.6370,0.2582)T=0.9230,РCR(3)=CR(2)+CI(3)/RI(3)=0.0332+0.0269/0.9230=0.0624<0.1Р结论РP3(定结县),权重为0.4015.РP5(仲巴县),权重为0.1735РP2(定日县),权重为0.1597.РP1(吉隆县),权重为0.1428.РP4(岗巴县),权重为0.1225.Р七、模型的改进

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