, Ec=2.8×104N/mm2Р内力标准值:Mk=Mγg=23001.2=1916.7KN Mq=0 Р由于ρ'=0, 所以θ=2Рρte=AsAte=As0.5bh=68860.5×380×1350=0.0268РαEρ=EsEc∙Asbh0=2.0×1052.8×104×6886380×1260=0.10Рσsk=MkAsηh0=1916.7×1066886×0.87×1260=254(N/mm2)Рψ=1.1-0.65ftkρteσsk=1.1-0.65×1.780.0268×263=0.930Рγf'=bf'-bhf'bh0=800-360×200380×1290=0.175Р短期截面刚度:РBs=EsAsh021.15ψ+0.2+6αEρ1+3.5γf'=2.0×105×6886×126021.15×0.930+0.2+6×0.101+3.5×0.175=1.32×1015(N∙mm2)Р截面刚度:РB=MkMqθ-1+Mk∙Bs=Bs=1.32×1015(N∙mm2)Р挠度:Рf=SMkl02B=548×1916.7×106×2160021.32×1015=70.37mmР由于l0=21.6m>9m,flim=l0300=21600300=72mmР显然f<flim ,挠度满足要求。Р五、主梁裂缝宽度验算Р对受弯构件:αcr=2.1 ;保护层厚度取:c=25mm ,带肋钢筋:ν=1.0Рdeq=nidi2niνidi=8×282+4×2528×1.0×28+4×1.0×25=27.07mmРωmax=αcrψσskEs1.9c+0.08deqρte=2.1×0.930×2632.0×105×1.9×25+0.08×27.070.0268=0.318mmР环境类别一类,裂缝控制等级为三级时,ωlim=0.40mm>ωmax=0.332mm ,裂缝宽度满足要求。