y11=y2;xv1=xv2;yv1=yv2;xa1=xa2;ya1=ya2;Р x2=xc;y2=yc;xv2=0;yv2=0;xa2=0;ya2=0;Р RPR();Р l=r=d3;af=0;ct=ct2;cv=cv2;ca=ca2;Р x1=xc;y11=yc;xv1=0;yv1=0;xa1=0;ya1=0;Р SSL();Р if ( ct2 < 0 ) ct2 += 2*PI;Р ct2 *= 180/PI;Р cout<<" CT3="<<ct2<<" "<<"CV3="<<cv2<<" "<<"CA3="<<ca2<<"\n";Р l1=d4;m=-1;Р ct2=0;cv2=ca2=0;Р x1=x2;y11=y2;xv1=xv2;yv1=yv2;xa1=xa2;ya1=ya2;Р x2=xg;y2=yg;xv2=0;yv2=0;xa2=0;ya2=0;Р RRP();Р if ( ct1 < 0 ) ct1 += 2*PI;Р ct1 *= 180/PI;Р cout<<" CT4="<<ct1<<" "<<"CV4="<<cv1<<" "<<"CA4="<<ca1<<"\n";Р cout<<" Xe="<<l2<<" "<<"Vxe="<<lv2<<" "<<"Axe="<<la2<<"\n";Р cout<<" ---------##########--------- \n";Р c1 += df;Р }Р cout<<" 结束";Р cin>>df;Р}Р输出结果:Р3-6图示四杆机构中,lAB=60mm,lCD=90mm,lAD=lBC=120mm,w2=10rad/s.试用瞬心法求:Р当φ=165°时,C点的速度Vc.Р当φ=165°时,构件三的BC线上(或其延长线上)速度最小的E点的位置及其速度的大小。Р当Vc=0时,φ角之值。(有两个解)
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