EKe9??TyxyxeWRhqRWhqWRRR???????????33363303011由??????eeeRaK?得到下列矩阵方程组:?????????????????????????????????????????????????????33363000030301122WRhqRWhqWRRuyxyx?化简得:??????????????????????????3640035353022WhquE?可得:??????????????????EWEhqu363567022?将??????22?u代入下式:???????????????????????????????????????????431274252151273321352594140012535035250215250254150191009353EKe10??????????????????????????????????????????????????333425135025103533031122WRhqRWRRuEyxyx?固定面上的反力:ahgaghq330?????从而可得支座反力为:43221234120303011hqWRhqWRWhqRWRyxyx????????这是y的线性方程,但相容方程要求它有无数多的解(全柱内的y值都应该满足它),可见它的系数和自由项都应该等于零,即0)(414?dxxfd,0)(424?dxxfd这两个方程要求ICxBxAxxf????231)(,KJxExDxxf????232)(代入应力函数表达式,并略去对应力分量无影响的一次项和常数项后,便得2323)(ExDxCxBxAxy??????对应应力分量为022????yx??gyEDxBAxyxy???????????26)26(22CBxAxyxxy?????????2322??以上常数可以根据边界条件确定。
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