二级直齿圆柱齿轮减速器_(机械设计课程设计)文档

.22X109/4.877=1.275X109РN1=6.22X109РN2=1.28X109Р(7)接触疲劳强度寿命系数KHNР由[1]P203图10-19РKHN1 = 0.90РKHN2 = 0.95Р KHN1 = 0.90РKHN2 = 0.95Р(8)计算接触疲劳强度许用应力[σH]Р取失效概率为1%,安全系数为S=1,由[1]式10-12得Р[σH]1= =0.90X600/1=540 [σH]2= Р =0.95X550/1=522.5 Р[σH]1= 540Р[σH]2= 522.5Р(9)试算小齿轮分度圆直径Р按[1]式(10-21)试算Р=37.8225РmmР37.823Р(10)计算圆周速度vРV=3.14X37.823X1440/60X1000=2.85034Рm/sРV=2.85Р(11)计算齿宽BРb = φdd1tРB1=1×37.823РmmРB1=37.823Р(12)模数Р=37.823/24=1.576Рh = 2.25mnt =3.546Рb/h =37.823/3.546=10.5769Р度Р=1.576Рh =3.546Рb/h= 10.577Р(13)计算载荷系数KР由[1]表10-2查得使用系数Р根据v= 2.85级精度,由[1]P190图10-8查得动载荷系数1.10Р由[1]表10-4P194查得РKHβ=1.12+0.18(1+0.6φd2) φd2+0.23×10-3b=1.12+0.18(1+0.6X)+Р0.23X10-3X37.823=1.417Р由[1]图10-13P195查得KFβ=1.34假定,由[1]P193表10-3查得1.2故载荷系数K=KAKVKHαKHβ=1X1.10X1.2X1.417=1.870РK=1.870Р(14)按实际的载荷系数校正分度圆直径Р由[1]式10-10aРd1=d1t=