5x + 0.5y = 0.1803 (1) 0.5x(143.32/58.44)+ 0.5y(143.32/74.56)= 0.3904 (2) 由(1)(2 )解得: x= 16.52% ;y= 19.54% 7. 解:化学计量关系为: 2P ~ MgNH 4 PO 4~ Mg 2P 2O 7 P 2O 5~ MgNH 4 PO 4~ Mg 2P 2O 7 P% =[0.2825 × (2× 30.97/222.60)/0.4530] × 100% = 17.35% P 2O 5~ MgNH 4 PO 4~ Mg 2P 2O 7 P 2O 5% =[0.2825 × (141.95/222.60)/0.4530] × 100% = 39.77% 8. 解: SiO 2% =[(0.2630-0.0013)/0.4817] × 100% = 54.33% E =(0.2630/0.4871) × 100% - 54.33% = 0.27% 9.解: 10. 解: 11. 算下列换算因数(1) 解: M(PbCrO 4 )=323.19 M(PbO 2 )=239.20 (2 )解; M(K 2 Cr 2O 7 )=294.18 M(Cr)=52.00 (3 )解: M(Na 2 S)=78.04 M(S)=32.07 (4 )解: M(Mg 2P 2O 7 )=222.55 M(MgO)=40.30 (5) 解: M((NH 4) 3 PO 4 12MoO 3 )=1876.35 M(P 2O 5 )=141.95 12 .解: M( NiC 8H 14N 4O 4) =288.91 M(Ni)=58.69 13 .解: M(K 2O) =94.20 M(KB[C 6H 5] 4 )=358.3 14 .解: m(SiO 2 )=0.2550-0.0015=0.2535g
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