液化天然气加注站损耗管理解析

= Aa? AO BOl l = 2201248 .1s m n CBa = 25? BCl = 201785 .0s m 对于 C点 Ca = Ba + n CBa + t CBa 方向: //' XX B→ 4O C→B BC ?大小: ?√√? 由 n CBa = 25?? BCl = 201785 .0s m , Ba = Aa? AO BOl l = 2201248 .1s m 已知, 根据根据加速度图可得: Ca = a?''cpl = 2617683 .0s m , t CBa = a?'''cnl = 29942344 .0s m 加速度分析图: 图 1-5 3 .对位置 9 点进行速度分析和加速度分析(a) 速度分析取速度比例尺 l?= mm s m001 .0 对A 点: AV = AV + AAV 方向: 4 BO ?AO 2?//BO 4 大小: ?√? AV = l?? 4pa =s m mm mm s m3289949 .09949 .328 001 .0?? 4?= AO Al V =s r mm s m044034 .1 315119 .0 3289949 .0? AAV = l? aal =s m mm mm s m60782497 .082497 .607 001 .0?? V B=V B= 4?? BOl =s m56377824 .0 对于 C 点: CV = BV + CBV 方向: //' XXBO 4? BC ?大小: ?√? CV = l?? pcl = mm s m001 .0s m mm 5518355 .08355 .551 ??V = l?? bcl = mm s m001 .0s m mm 1436768 .06768 .143 ?? 5?= bcl CBlu V =s r06427 .1 速度分析图: 图 1-6