j=1:5Рif i~=jРH(i,i)=H(i,i)+U(i)*U(j)*(G(i,j)*sin(e(i)-e(j))-B(i, j)*cos (e(i)-e(j))); РN(i,i)=N(i,i)-U(i)*U(j)*(G(i, j)*cos(e(i)-e(j))+B(i,j)*sin(e(i)-e(j)));РM(i,i)=M(i,i)-U(i)*U(j)*(G(i,j)*cos(e(i)-e(j))+B(i,j)*sin(e(i)-e(j))); L(i,i)=L(i,i)-U(i)*U(j)*(G(i,j)*sin(e(i)-e(j))-B(i,j)*cos(e(i)-e(j)));РendРendРN(i,i)=N(i,i)-2*(U(i))^2*G(i,i);РL(i,i)=L(i,i)+2*(U(i))^2*B(i,i);РendРJ=[H,N;M,L] %J 为雅克比矩阵Рox=-((inv(J))*fx);Рfor i=1:4Рoe(i)=ox(i); oU(i)=ox(i+4)*U(i);РendРfor i=1:4Рe(i)=e(i)+oe(i); U(i)=U(i)+oU(i);РendРcount=count+1;РendРox,U,e,countР%求节点注入的净功率Рi=5;Рfor j=1:5РP(i)=U(i)*U(j)*(G(i,j)*cos(e(i)-e(j))+B(i,j)*sin(e(i)-e(j)))+P(i);РQ(i)=U(i)*U(j)*(G(i,j)*sin(e(i)-e(j))-B(i,j)*cos(e(i)-e(j)))+Q(i);РendРS(5)=P(5)+Q(5)*sqrt(-1);РSР%求节点注入电流РI=Y*U'Р运行结果РY值:Р迭代过程:Р电压值:Р平衡节点注入功率及电流:Р五、课程设计心得与体会
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