1) m<l (2) 3<m<l.\r?.\ro?`[(1)èpð?ñ4 = (-6) 2-1 (2m+l) >0,ò?@E\r(2)¶óBp\róñXI+X2=6, xiX2=2m+l,+ô2XIXZ+XI+X2N20ñ2 (2m+l) +6>20,ò?@È\rô (1)pxE6?õ¿ö÷pm pÂÁÃÄ.\ro??[\r(1)?ðA = (-6) 2Ì1 (2m+l) >0,\r m<l\r(2)?ð XI+ X2=6, xiX2=2m4-l,\rÞ 2XIX2+XI+ X2N20,1* 2 (2m+l) + 6 > 2 0 , ? m23,\rÞ m=l,1 * m pÃÄA3gmWl.\r27(1)øùúûü20ýþ7øùÿ30 0(2)@P420`p.\r(1)\r??x ??y = x 1600`!"#$%&#$'(\r)50 *+,-./x, y 01`23456\n7*+,-80\r(2)9:;<==>?@-BC*+D-8.\rE\r(1)\r??'x ??y \rx+y=50\r20x + 40y = 1600,\r)\rx=20\ry = 30.\r{\r : ??F20 ??30 .\r(2)26 x 20 + 50x30-1600 = 420(` ).\rHIJ'(KLMNO@P420`p.\rPQ\rCRSTU1`234560V \nR0.WXI(1)YZ[.\]^_-1`234560(2)9:.\,\r_abc.