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铁路选线设计范例

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50.4055.405471.2770.8300.600.3890.389860.6980.4192.110.50.17410.67424.52.4495.1430.300.4300.430860.6980.2091.0-10.50.167-10.33760.7890.7891.45-10.60.145-10.46760.7891.1441.45-10.20.463-9.737770.7791.1300.85000850.7060.600∑tiL=13.267min计算得,向阳站(A)到东风站(B)之间的往返运行时分如下:A→B∑tiL=16.443minB→A∑tiL=13.267min起停附加时分tq+tt=3min半自动条件下,列车会车与不同时到达间隔时分TA→B=TW=16.443+3=19.443minTB→A=TF=13.267minTZ=19.443+13.267+6=38.71min通过能力:N=1440-TTTZ=1440-3038.71=36.42对/d,取36对/d。NPt=N1+∝-Nkεk+NLεL+NZεZ+NkHεkH=361.2-2×1.3+1×2+2×1.5+1×1.2=30-8.8=21.2对/dNH=NPt+NLμL+NZμZ+NkHμkH=21.2+1×0.5+2×0.75+1×0.75=23.95对/d二.输送能力C=365NHGJ106β=365×23.95×1476.00106×1.15=11.22Mt/a>9Mt/a,运量满足要求。以上计算中:TT—日均综合维修天窗时间,取30min;μ—满轴系数,μL=0.5,μZ=0.75,μkH=0.75;ε—扣除系数,εk=1.3,εL=2.0,εZ=1.5,εkH=1.2;∝—储备系数,0.2。三.输送能力检查及评价经以上检查,线路设计输送能力满足任务书要求的运输任务,且富余量较多。

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