, customer c where not existsР(Рselect * from buy as y where y.customerno in (select customerno from customerРwhere customername = 'Dennis' )Рand not exists (Рselect * from buy as z where z.customerno?= x.customerno and z.productno =Рy.productnoР)Р)Рand x.customerno = c.customernoР( 3)求牙膏卖出数量最多的供应商。Рselect p.supplier,sum(num) from product p,customer c, buy bРwhere p.productno = b.productno and c.customerno = b.customerno and sort = ' 牙Р膏 'Рgroup by p.supplierРhaving?sum(num) > = allР(Рselect sum(num) from product p,customer c, buy bРwhere p.productno = b.productno and c.customerno = b.customerno and sort = ' 牙Р膏 'Рgroup by p.supplierР)Р( 4)Р'Рupdate product set price = price * (1+0.1) where sort = 牙膏 ';Р( 5)Рdelete from?product where productno not in (select distinct productno from buy );