规律:袆羆这两中曲线都既无刚性冲击。节在凸轮设计过程中,选择基圆半径为80MM的对心凸轮,其推程和回程都为70.mm选择推程转角为80度。回程转角为190度,无远休但有近休。蝿凸轮设计计算转角与位移的对应数据如下:罿0肆80蚃125蒀121.0777蚈245膆82.11076肃5袈80.15528蒆130芆119.0633膀250薀81.47037芅10芆81.12366薁135肈117.0351芈255莆80.94343羂15螀83.41383肇140蒅115莃26080.531732087.24609145112.964926580.236662592.60042150110.936727080.059213099.26453155108.92232758035106.8819160106.92842808040115165104.96192858045123.1181170103.02932908050130.7355175101.13722958055137.399618099.292033008060142.753918597.53058065146.586219095.767193108070148.876319594.099453158075149.844720092.50243320808015020590.981543258085135.900621089.541923308090134.232821588.188443358095132.522086.9256934080100130.70822585.7579334580105128.862823084.6891135080110126.970723583.7228635580115125.038124082.86244120123.0716表2-5第三章机构模拟分析(一)(二)第四章传动系统的方案设计
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