取Р Р?取采用双肢箍筋(n=2),箍筋间距为100mm,箍筋直径为8mm相应的配筋率为Р rsv = Asv/bs = 2×50.3/(250×100) = 0.402% > rsv,min = 0.191%Р Р?满足要求Р?6.10 计算抗扭钢筋Р?根据混凝土结构设计规范7.6.8-3Р T≤btWt + 1.2fyvР 因为 z = 1.20,Np0 = 0Р ≤1.309× + 1.2×Р 解上方程?Р Astl = z = 1.20×0.20× = 198mm2Р <Astl,min = 393.mm2Р?取?Astl = Astl,min = 394mm2Р?6.11 计算受弯钢筋Р ecu = 0.0033 - (fcu,k - 50)×10-5 = 0.0033 - (30 - 50)×10-5 = 0.0035 > 0.0033Р 取 ecu = 0.0033Р 按混凝土结构设计规范(7.1.4-1)Р xb = 0.55Р 按混凝土结构设计规范(7.2.1-1), A's = 0, A'p = 0Р M = Р x = h0 - = 420 - 17mmР < xbh0 = 0.55×420 = 231.00mmР 按混凝土结构设计规范(7.2.1-2)Р a1fcbx = fyAsР 得?As = 202mm2Р?最小配筋率Р Р As< Asmin = rminA = 0.0021× = 241mm2Р?取As = 241mm2Р?取A's = Asmin = 241mm2Р?6.12 梁钢筋划分Р 顶部纵向钢筋面积Atop = A's + Astl·Р 底部纵向钢筋面积Abot = As + Astl·Р 每侧面纵向钢筋面积Amid = Astl·Р?腹板顶部纵向钢筋实际配筋:3B16Р?腹板底部纵向钢筋实际配筋:4B16Р?单侧中部: 2B16