|0.5833/4.0833|=0.1485 |1 1/5 1/7| 对行求和| 1.3429 |求均值|0.4476 |规化|0.4476/6.2254|=0.0719 B3= |51 1/3| --------- ?| 6.3333| ------- ?|2.1111 | ------ ?|2.1111/6.2254|=0.3391 |73 1|| 11|| 3.6667| |3.6667/6.2254|=0.5890 (3) 一致性检验,分析专家评估矩阵的合理性|1 1/2 2| |0.309| |0.8975| AW= |21 3|· |0.529| = |1.633| |1/2 1/3 1| |0.162| |0.4928| Λ=1/3 × (0.8975/0.309+1.633/0.529+0.4928/0.162)=1/3 × (2.9045+3.0869+3.0420)=3.011 CI=( Λ- 3)/(3-1)=(3.011-3)/(3-1)=0.0056 CR=CI/RI=0.0056/0.58=0.0096<0.1 所以通过一致性检验。(4)计算综合重要度先后顺序|0.6328 0.5714 0.0719| |0.309|=0.5094 0.6328 × 0.309+0.5714 × 0.529+0.0719 × 0.162=0.5094 自主研发 1 |0.3019 0.4082 0.3391| · |0.529| =0.3642 0.3019 × 0.309+0.4082 × 0.529+0.3391 × 0.162=0.3642 改良现有设备 2 |0.0654 0.1485 0.5890| |0.162| =0.1941 0.0654 × 0.309+0.1485 × 0.529+0.5890 × 0.162=0.1941 引进国外设备 3