)γ 22]/(β 17-β 23)=[(6.29-9.50 ) *0.04+(57.00-6.29)*0.74]/ (50.00-6.29 )=0.86 γ 23=γ 17+γ 25-γ 22=0.86+0.04-0.74=0.16 由: γ 14+γ 23=γ 17+γ 18;γ 14β 14+γ 23β 23=γ 17β 17+γ 18β 18得: γ 14=[(β 18-β 23)γ 23+(β 17-β 18)γ 17]/(β 14-β 18)=[(5.22-6.29 ) *0.16+(50.00-5.22)*0.86]/ (40.00-5.22 )=1.10 γ 18=γ 14+γ 23-γ 17=1.10+0.16-0.86=0.40 由: γ 29=γ 30+γ 31;γ 19β 19=γ 30β 30+γ 31β 31得: γ 30=(β 29-β 31)γ 31/(β 30-β 29)=(1.11-0.81 )*1.84/ (2.43-1.11 )=0.42 γ 29=γ 30+γ 31=2.26 由: γ 27+γ 30=γ 28+γ 29;γ 27β 27+γ 30β 30=γ 28β 28+γ 29β 29得: γ 27=[(β 28-β 30)γ 30+(β 29-β 28)γ 29]/(β 27-β 28)=[(3.40-2.43 ) *0.42+(1.11-3.40)*2.26]/ (1.25-3.40 )=2.22 γ 28=γ 27+γ 30-γ 29=2.22+0.42-2.26=0.38 由: γ 20+γ 28=γ 26+γ 27;γ 20β 20+γ 28β 28=γ 26β 26+γ 27β 27得: γ 20=[(β 26-β 28)γ 28+(β 27-β 26)γ 27]/(β 20-β 26)=[(3.80-3.40 )
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