三相短路故障分析与计算及其程序设计

0.3327111Yj15.785433j0.105j0.2662j0.3992第9页共16页1YYj3.75663553j0.2662正11Yj14.523844j0.105j0.2文1YYj9.52343443j0.105111Yj16.286155j0.105j0.3327j0.26621YYj9.52345665j0.1051Yj9.523466j0.105导纳矩阵中其他元素为0由此得到图4-3所示网络的导纳矩阵为j7.2619j4.76190000j4.7619j10.2726j2.50500j3.005700j2.5050j15.7854j9.5234j3.75660Y00j9.5234j14.5238000j3.0057j3.75660j16.2861j9.52340000j9.5234j9.5234对该导纳矩阵求逆得到网络的阻抗矩阵为j0.2614j0.1886j0.1056j0.0693j0.1425j0.1425j0.1886j0.2877j0.1611j0.1056j0.2174j0.2174j0.1056j0.1611j0.2244j0.1471j0.1962j0.1962Zj0.0693j0.1056j0.1471j0.1653j0.1287j0.1287j0.1425j0.2174j0.1962j0.1287j0.3535j0.3535j0.1425j0.2174j0.1962j0.1287j0.3535j0.4585运用第6列的元素来求短路电流和各节点电压j1j1IF2.181Z66j0.4585Z160.1425U1j1j1jj0.689Z660.4585第10页共16页