.............................................1分联立解得R=0.1m.......................................................................................................................................1分(3)设轨道在最低点对小车的支持力大小为FB′,由牛顿第二定律有 FB′−mg=mvB2R.........................................................................................................................................2分解得FB′=60N...............................................................................................................................................1分由牛顿第二定律可知,小车对轨道的压力FB=FB′=60N......................................................1分第二部分选答题(选修模块共20分)四、选择题(本大题共4小题,每题2分,共8分)23.(1)(1-1)A(2)(3-1)C24.(1)(1-1)D(2)(3-1)C25.(1)(1-1)D(2)(3-1)D26.(1)(1-1)D(2)(3-1)D五、填空题(每空2分,共4分)27.(1)(1-1)340不变(2)(3-1)变大 不变三、计算与简答题(共8分)
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