+ 2s + h = 200+2*0+120 = 320mm Р 3.2.1.2 bcy = bty + 2s + h = 600+2*0+120 = 720mm Р 3.2.2 局部荷载的有效分布宽度Р 3.2.2.1 按上下支承考虑时局部荷载的有效分布宽度Р当 bcy ≥ bcx, bcx ≤ 0.6Ly 时,取 bx = bcx + 0.7Ly = 320+0.7*7000 = 5220mm Р当 bx > Lx 时,取 bx = Lx = 4000mm Р 3.2.2.2 按左右支承考虑时局部荷载的有效分布宽度Р当 bcx < bcy, bcy ≤ 2.2Lx 时,取Рby = 2bcy / 3 + 0.73Lx = 2*720/3+0.73*4000 = 3400mm Р当 0.5by > 0.5ey2 时,取 by = 1700 + 0.5ey2 = 1700+0.5*1650 = 2525mm Р 3.2.3 绝对最大弯矩Р 3.2.3.1 按上下支承考虑时的绝对最大弯矩Р 3.2.3.1.1 将局部集中荷载转换为 Y 向线荷载Р qy = N / bty = 35/0.6 = 58.33kN/m Р 3.2.3.1.2 MmaxY = qy·bty·(Ly - y)·[y1 + bty·(Ly - y) / 2Ly] / Ly Р= 58.33*0.6*(7-2.675)*[2.375+0.6*(7-2.675)/(2*7)]/7 = 55.37kN·m Р 3.2.3.2 按左右支承考虑时的绝对最大弯矩Р 3.2.3.2.1 将局部集中荷载转换为 X 向线荷载Рqx = N / btx = 35/0.2 = 175kN/m Р 3.2.3.2.2 MmaxX = qx·btx·(Lx - x)·[x1 + btx·(Lx - x) / 2Lx] / Lx
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