2343建筑测量最新整理前12次考题汇总

)/2=357.28mK=(357.33一357.23)/357.28=0.10/357.28=0.00028CD段:DCD=(248.73-1-248.63)/2=248.68mK=(248.73一248.63)/248.68=0.10/248.68=0.00040AB段丈量的结果较精确。26.现需从A点测设长度为129.685m的水平距离AB,初设B点后,测得温度t=23℃,AB两点的高差h=-1.168m,已知尺长方程为lt=30-0.0023+1.2×10-5(t-20°C)×30m,问需沿地面测设多少长度?解:尺长改正△ld=-0.0023/30×129.685=-0.0099m温度改正△lt=1.2×10-5(23-20)×129.685=0.0047m倾斜改正△lh=-1.1682/129.685=-0.01052m需沿地面测设长度DAB′=129.685-(-0.0099)-0.0047-(-0.01052)=129.701m27.一附合水准路线的高差观测成果及测站数如下表,请在表格内按测站数调整闭合差并求出各点的高程。1.如图所示,闭合水准路线含四个测段,求出1、2、3点的高程。.2.竖直角观测成果整理:3.在A点以B点为已知方向用极坐标法测设P点,已知0081210?????BA?,0060208?????AP?,试求测设角值。解:008130180????????BAAB??0074177???????ABAP???1.如图所示,已知水准点BM,高程为10.648m,闭合水准路线计含4个测段,各段测站测站目标竖盘位置竖盘读数′″半测回角°′″指标差″一测回角°′″备注DP左942318-42318-21-42339盘左视线水平时读数为90°,视线上斜读数减少右2653600-42400K左82360072400-1872342右277232472324