0.0093)×5.59×3.6+(0.0892+0.2×0.0210)×1.4×3.6=3.025+1.695=4.72kN•m22m2=(0.0093+0.2×0.0399)×5.59×3.6+(0.0210+0.2×0.0892)×1.4×3.6=1.252+0.705=1.957kN•m,,,2m1=m1=-0.0826×6.99×3.6=-7.483kN•m,,,2m2=0,m2=-0.0570×6.99×3.6=-5.097kN•m224区格板:l01/l02=2.4/3.6=0.667,g=4.19kN/mq=1.4qk=1.4×2.5=3.5kN/mq/2=1.75kN/m2p=g+q=7.69kN/m222m1=(0.0098+0.2×0.0341)×5.59×3.6+(0.0278+0.2×0.072)×1.75×3.6=1.204+0.957=2.161kN•m22m2=(0.0341+0.2×0.0098)×5.59×3.6+(0.072+0.2×0.0278)×1.75×3.6=2.612+1.759=4.371kN•m,,,2m1=m1=-0.0826×7.69×3.6=-8.232kN•m,,,2m2=m2=-0.0570×7.69×3.6=-5.681kN•m2223区格板:gk=3.49KN/mqK=2.5kN/mp=1.2gk+1.4qk=7.69kN/m取1m板宽为计算单元,按弹性理论计算,计算跨度取为l0=2.4m。如果3区格两1端完全简支的情况,则跨中弯矩为M=Pl2,考虑到3区格板两端的嵌固作用,故跨中8011弯矩取为M=Pl2;如果3区格两端完全嵌固的情况,则支座弯矩为M=−Pl2,1001201考虑到3区格板两端不是完全嵌固作用,故支座弯矩取为M=−Pl2。1403区格的板的弯矩计算表见下表4-110老牛设计870555454
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