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混凝土结构设计原理 第四版 沈蒲生 课后答案[3-7章]

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90mm S =226 mm S =2233 mmР 1 2 2 3 4 2 4 4Р 2 f 2 f 2Р 1 =1.0 , fc =14.3 N/ mm , y =300N/ mm , y =300N/ mm , b =0.550Р xР fyAsfAys 3002233300226Р x = 1 fbc = 1.014.3200 =210.5mmР 120mm=2 as < x < b h0 =214.5mmР (2)Р xР fР M u = y AS h0 as + 1 fc b x ( h0 2 )Р210.5Р =300 226 (390 60)+14.3 200 210.5 (390 2 )Р =194 kN mР b hР4 17 T f =500mm b=250mm h=600mm f =100mmР C30 HRB335 M=256kN mР1 as=60mmР hР 0 =h as=600 60=540mmР 1 2 2 3 4 2 4 4Р 2 f 2Р 1 =1.0 , fc =14.3 N/ mm , y =300N/ mm b =0.550Р2 TР h f 100Р b hР 1 fc f f h0 2 =1.0 14.3 500 100 540 2Р =350 kN m> M u =256 kN mР TР3 ASР M 256106Р 2Р fbh 2Р s = 10cf =5005401.014.3 =0.1207Р 12Р =1 s=0.1310< b =0.550Р 1fc 1.014.3Р bh f 2Р AS = f 0 y =0.1310 500 540 300 =1686 mmР 2Р AS min bh=0.215% 250 600=323 mmР 2Р 2 16+4 20 AS =402+1256=1658 mmР 4

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