µ¶·§l¨©¸P¡¢r\r29CCh(g)+2NH3(g)=CO(NH2)2(s)+H2O(1)AH=-134kJ/molCO2+NH3H2O=NH4HCO30.13mol\r¹º®g
CO2l>2aJKP0@P`7'`-0@P`11.25\r®§\r(1)@ACD»(272kJ-138kJ)=134kJ,`CO2¼?\r½¾PdY\\rCO2(g)+2NH3(g)=CO(NH2)2(s)+H2O(1)AH=-134kJ/mol (2)¿¼ÀÁÂÃ?aPCO2g
ÄÅÆ\rÇ,dY\CO2+NHyH2O=NH4HCO3 P@ACD,pH\12.81P¼ÀÃ?2ÈÉPCO2Pq5\91.6%,\rQÈÉPCO2P0@P`Ê\x,@CO2+NHyH2O=NH4HCO3CDË=`¨@"°©/"@P"x91.6%,\r12%21AL!mol\r®Íx=0.13mol ÎÏiÐÑFE<HICO2ÈÉq5ÒIÓI?40@2ÈÉCChq5ÔÕPÖײØÄÅ\rÆǹº®g
CO2 (3)¿@bÙ7WCDÚÛS\JK2JkaÜ^`mÝa Aa\rÞßI2JKà``ábÝ$%PÞßI;0@P`â()â2H2(g)+CO(g)=CH30H(g)\r\???!&'P$%aJKP0@P`7'`-0@P`LPa>Pb pb2JK0@P`7\0.7,\r`\rCH30H(g)W2H2(g)+CO(g)AH=+90kJ/mol\rÜ^`(mol)100\rS`(mol)x2xx\r`(mol)1-x2xx\r]x\r------------------=0.7,®Íx=l/8mol,CDb2$%P`\l/8molx90kJ/mol=11.25kJo\r1$x+2x+x