30mT梁张拉钢绞线伸长量计算书

0015×7.101+0.225×0.2793)=1396.4KNΔLAB=(1500.1×3.007)/(1.97×105×8束×139×10-6)=20.6mmΔLBC=(1448.3×5.236)/(1.97×105×8束×139×10-6)=34.6mm大浏高速公路第二合同段30mT梁钢绞线张拉伸长量计算书湖南路桥·湖南省湘筑工程有限公司-10-ΔLCD连续端=(1396.4×7.101)/(1.97×105×8束×139×10-6)=45.3mmΔL=(ΔLAB+ΔLBC+ΔLCD连续端)×2=(20.6+34.6+45.3)×2=210.0mm4、中跨中梁8束连续端N2钢束从连续端至中心线分为AB段3007mm(含工作长度650mm)、BC段5236mm、CD段7101mm,合计长度15344mm;纵弯角度为10度,平弯角度为6度。P=193.9×8束=1551.2KN(详见设计图纸)θ=(10+6)°×π/180=0.2793连续端AB段:(直线段)P1=1551.2[1-e-(0.0015×3.007+0.225×0.2793))]/(0.0015×3.007+0.225×0.2793)=1500.1KN连续端BC段:(曲线段)P2=1500.1[1-e-(0.0015×5.236+0.225×0.2793))]/(0.0015×5.236+0.225×0.2793)=1448.3KN连续端CD段:(直线段)P3=1448.3[1-e-(0.0015×7.101+0.225×0.2793))]/(0.0015×7.101+0.225×0.2793)=1396.4KNΔLAB=(1500.1×3.007)/(1.97×105×8束×139×10-6)=20.6mmΔLBC=(1448.3×5.236)/(1.97×105×8束×139×10-6)=34.6mm