锅炉烟气体积密度计算推导（精选）

24MР③随理论空气量带入的水蒸气体积Р 设1kg空气中含有的水蒸气为d(g/kg),则标准状态下1.293d/1000kg.标准状态下,水蒸气密度为0.8031,即1干空气中含有水蒸气体积为0.001293d/0.8031=0.00161d.其中d为空气的绝对湿度,一般情况下可取d=10g/kg,则理论空气量带入的水蒸气为0.0161。Р所以,理论水蒸气体积为=0.0112H+0.0124M+0.0161Р 质量=ρ=0.8031*(0.0112H+0.0124M+0.0161)Р =0.08995H+0.00996M+0.0129Р出口温度为T,压强为PР体积:=υ=(0.08995H+0.00996M+0.0129)T/PР =(0.08995H+0.00996M+0.0129)*461.92T/PР =(41.55H+4.6M+5,96)T/PР3.理论烟气量Р 理论干烟气量=+=0.01866C+0.007S+0.79+0.008NР =Р =0.03663C+0.019985S+0.9867+0.009992NР ρ=/=Р 理论烟气量Р =+Р =0.01866C+0.007S+0.79+0.008N+0.0112H+0.0124M+0.0161Р =0.01866C+0.007S+0.008N+0.0112H+0.0124M+0.8061Р =+Р =0.03663C+0.019985S+0.9867+0.009992N+0.08995H+0.00996M+0.0129Р ρ=/Р =Р出口温度为T,压强为PР 烟气量=+++Р =6.922CT/P+2.596ST/P+(293+2.97N)T/P+(41.55H+4.6M+5,96)T/PР =(6.922C+2.596S+293+2.97N+41.55H+4.6M+5,96)T/PР =Р Ρ=/Р =