69AW.m+15.14AWxl.0mnnnVV3.O//2x2.0m2.0mx3.02m\09.3KPa3.8.2基础局度bt=0.45m,/?0=1.0-0.05=0.95m.bh=bt+2/z0=0.45m+2x0.95m=2.35mbh+bt?(0.454-2.35)znA?乂h,、2,3.0m0.45mAnc、,2.0m0.45mnncA=(-—f?)/7—(-—f—/?0)2=(———0.95m)x2.0m—(———0.95m)2=0.62m2F,=psA=143.1KPaxO.62m2=88.72KN按线性插值法得从=0.975F,<0.7/?hf(btnh、、=0.7x0.975x1.27W/誦2x1AOmx0.95m=H3QKN故基础高度满足要求.3.8.3基础底板配筋长方向弯矩计算=^-xl43.1^zx(3.0-0.45)2m2x(2x2.0+0.45)m=172.5^-短方向弯矩计算PnsA醐X+A⑽in_(】43.1+109.3)級\26.2KPa从n-n==^xl26.2尺/Vzx(2.0-0.45)2m2x(2x3.0+0.45)m二81.5A7V.m长边方向的受力钢筋截面面积AsI计算:=961mm2A_?_?172.5xlO6;V.mms,0.9hmfy0.9x0.95x103mmx210N/mm1配筋:100>12@200,4=1131醐2短边方向的受力钢筋截面面积Asn计算:Asn=n-n81.5xlO6;V"7m0.9/7nn/v?0.9x0.95x103mmx210A^/mm选筋:14010@200,As=1099mm2454mm岣瞧=34.88^./77,VAmax=15.4^,/VAmax=815.68^地基承载力特征值得修正:fa=fak+7jhr(b-3)+?(J-0.5)=180+1.5x20x(2.5-0.5)=2撇pa
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