东方防腐集团炉膛内搭拆架方案

b/3=0.35×1.1/3=0.128 kN/mР施工均布荷载Qk=qk×lb/3=3×1.1/3=1.1 kN/mРq=1.2G2k+1.4Qk=1.69 kN/mРMGk max=0.10G2k×la2=0.10×0.128×1.5×1.5=0.029 kN·mРMQk max=0.10Qk×la2=0.10×1.1×1.5×1.5=0.248 kN·mРM=1.2MGk max+1.4MQk max=1.2×0.029+1.4×0.248=0.382 kN·mР<f=205 kN/mm2Р抗弯强度满足要求。Р[v]=lb/150=1500/150=10 mmРv≤[v] 挠度满足要求。Р横向水平杆与立杆连接的扣件抗滑承载力验算Р横向水平杆传给立杆的竖向作用力:РR=(1.2NG2k+1.4NQk)/2=(1.2×0.5775+1.4×4.95)/2=3.812 kNРRc=8.00 kNРR≤Rc 扣件抗滑承载力满足要求。Р3.2.5、立杆计算Р单立杆竖向承载力:РN=1.2(NG1k+ NG2k)+0.85×1.4∑NQkР=1.2(H·gk1+7·gk2·la·lb/2)+0.85·1.4·n1·qk·la·lb/2Р=1.2(39.6×0.1248+7×0.35×1.1×1.5/2)Р +0.85×1.4×1×3×1.1×1.5/2Р=11.3 kNР kN·mР长细比:Р式中 k取1.155Р查JGJ130-2001表5.3.3,并用插入法得u=1.51Р查JGJ130-2001附录C表C得=0.182Р N/mm2<f=205 N/mm2Р立杆稳定性满足要求。Р3.2.6、连墙件计算(按锅炉观火孔设置)РNlw=1.4×ωk×Aw=1.4×0.658×2×1.8×3×1.5=14.92 kNРNl=Nlw+N0=14.92+5=19.92 kNРNl>Rc