×( 15- 0) +( 227.30+1024.10 × 0.003 ) × 4.2 ×( 15- 0) = LI 0 +27378kJ/d Q 4 =LI 2 +G 2×C m×(T 2-T 0) +W ×C 水×(T 2-T 0) = LI 2 +1024.10 ×( 1- 0.003 ) ×0.84 ×( 40- 0) +1024.10 ×0.003 ×4.2 ×( 40- 0) = LI 2 +34823kJ/d H 0 =0.622 ×Ф× P s?(P-ФP s) =0.622 ×0.64 ×0.8200 ?( 100 - 0.64 ×0.8200 ) =0.0033kg 水/kg 干空气 I 0=(1.01 +1.88 H 0)×t 0+2500 H 0=( 1.01 + 1.88 ×0.0033 ) ×19.3 + 2500 ×0.0033 =27.86kJ/kg 干空气 H 1 =H 0I 1=( 1.01 + 1.88 H 1) ×t 1+ 2500 H 1=(1.01 +1.88 ×0.0033 )×70+2500 ×0.0033 =79.38kJ/kg 干空气由 Q 1+ Q 2+ Q 3=Q 4+ Q 5+ Q 6,设 Q 5+ Q 6 =0.05 Q 2, Q 3 =0得 LI 0 +27378 +Q 2= LI 2 +34823 +0.05 Q 2 0.95 Q 2 =7445+ L(I 2-27.86 )①对水进行物料平衡计算得 LH 1+ W= LH 2, 又因为 H 1 =H 0 =0.0033kg 水/kg 干空气故W=L(H 2-H 0)=L(H 2-0.0033 ) =227.30 ②对空气的加热量进行衡算得 LI 0+ Q 2 =LI 1, 又因为 I 0 =27.86kJ/kg 干空气 I 1 =79.38kJ/kg 干空气
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