20??????T所以)(71.54852??T由0??X得0cossincos12??????TGT030cos30sin8000cos605485.710100?????T10所以)(98.77851??T由0??Y得0sincossin12?????????TGT所以)(96.1557130sin98.778530cos800060sin71.5485000???????????答:答:起吊钢绳所受的拉力为5485.71N,制动绳所受的拉力为7785.98N,地面A点时混凝土杆的反力为15571.96N。5(Jd1D3095).安装螺栓型耐张线夹时,导线型号为LGJ一185/25,金具与导线接触长度为?1L250mm,采用l×10mm铝包带,要求铝包带的两端露出线夹10mm,铝包带两头回缠长度为c=110mm,已知LGJ-185/25型导线直径d=18.9mm,求所需铝包带长度L带?解:按题意求解如下。(1)铝包缠绕导线的总长度10221????cLL=250+2×110+2×10=490(mm)(2)铝包带的总长L带??Lbd)(??306310490)19.18(?????(mm)答:所需铝包带长度为3063mm。6(Je1D3096).某110kV架空线路,通过Ⅵ级气象区,导线型号为LGJ-150/25,档距为300m,悬挂点高度h=12m,导线计算直径d为17.1mm,导线自重比载g1为34.047×10-3N/m·mm2,最低气温时最大应力max?为113.68MPa,最高气温时最小应力min?为49.27MPa,风速下限值minV为0.5m/s,风速上限值maxV为4.13m/s。求防震锤安装距离L。解:最小半波长1minmaxmin81.94002gvd???233,110047.3427.4981.913.44001.173??????(m)最大半波长
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