15 (5 + 1 2 ) = 20 119 (51 2 + 611 + 6) = 200 11 = 6 =\r19. 83\r( 7 ) µ¶·¸¹ºa f * ( s ) = ( s + 5) 2 + 25 = s 2 + 10s\r+ 5 0 ?? ½·¸¹ºa\rs 0 5 1 0 f ( s ) = si ( A bK ) = + [kl 0 2 0 s 6\rk2 ]\r= s 2 + ( 5 + 2 k 2 ) s + (10k 2 2kl + 6) f (s) = f * ( s)\rk 2 = 2. 5 (5 + 2k 2 ) = 10 19 (10k 2 2kl + 6) = 50 kl = 2 = 9. 5\rK = [kl\rk 2 ] = [9. 5 2, 5]\r( 8 ) ~T\r??`a\r& x = ( A LC ) x + Bu + L y & x = Ax + Bu + L ( y y )\r& 5 1 x + Ou + 19.83 ( y y ) x= 0 2 15 6\rrs¤¥fghihB3 - 5 - 1 1 h 2 lma\rPage 83 of 84\r<=?>?@ABCD\rvictory JK\rr\ru\ro ( A, B, C )\ry.\r19. 83 9.5\rxl\r6 5\r& xl\r15 y\ru\r2\r2.5\rx2\r& x2\rB 3-5-11 h 2\rPage 84 of 84\r1
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