c语言编程113道

;k++)\r{printf("%3d",c[k]);}\rprintf("\n");\r)\r113.\r,(FGHIJK3, 5, 7 ,L( ?MNOPQ:\r( 1 ) ISTK3, 5, 7 ,LU\r(2 ) IKWX(YZ[X),LU\r( 3 ) IKW(YZ[),L$\r#include<stdio.h>\rvoid main()\r{\rint a;\rprintf("%\r],\n");\rscanf("%d",&a);\rif(a%3==0&&a%5==0&&a%7==0)\rprintf("%d ISTK 3, 5, 7 ,L\n",a);\relse if(a%3 !=0&&a%5=0&&a%7=0)\rprintf("%d ISTK 5, 7 ,L\n",a);\relse if(a%3==0&&a%5!=0&&a%7=0)\rprintf("%d ISTK 3,7 ,L\n",a);\relse if(a%3=0&&a%5=0&&a%7!=0)\rprintf("%d ISTK 3,5 ,L\n",a);\relse if(a%3=0&&a%5!=0&&a%7!=0)\rprintf("%d IK 3 ,L\n",&a);\relse if(a%3 !=0&&a%5==0&&a%7 !=0)\rprintf("%d IK 5 ,L\n”,a);\relse if(a%3! =0&&a%5! =0&&a%7==0)\rprintf("%d IK 7 ,L\n",a);.\relseprintff%d ^IK 3, 5, 7 ,L\n",a);