k][3]+b[k][4])/5;\rfor(k=0:k<6;k++)\r{printf(H%3d",c[k]);}\rprintf("\n");\r113 .??0@ !"#$3, 5, 7 %@&?'()*+?:.\r1"-.$3, 5, 7 %\r/2"$0120/34?52?06%:\r/3"$017?0/34?5?06%\r#include<stdio.h>\rvoid main\r/\rint a;\rprimf/"97?0\n"\rscanf":d”,&a;\rifa%3==0&&a%5==0&&a%7==0\rprintf"%d "-.$ 3 5, 7 %\n",a;\relse ifa%3! =0&&a%5==0&&a%7==0\rprintf"%d "-.$ 5, 7 %\n”,a;\relse ifa%3=0&&a%5!=0&&a%7==0\rprintf"%d "-.$ 3,7 %\n”,a;\relse ifa%3==0&&a%5==0&&a%7!=0\rprintf"%d"-.$3,5%\n 'a;\relse ifa%3==0&&a%5 !=0&&a%7 !=0\rprintf"%d "$ 3 %\n”,&a;\relse ifa%3!=0&&a%5==0&&a%7!=0\rprintf"%d "$ 5 %\n",a;\relse ifa%3!=0&&a%5!=0&&a%7==0\rprintf"%d "$ 7 %\n”,a;\reke printf"%d ;"$ 3, 5, 7 %\n”,a;\r}