大学物理(下册)习题册答案

ë#\r1 4 c ì K l ·\rN = 0.3 x 6.023 x 1023 x 1.3 x lO -12 = 2.35X1011\ro\rhíÎÏÐÙÚuî\r½ï?uðl·\r4 ñò = (1"2)ô / T = 0.693 X 2.35 X1011 / (5730 X3.156 x 107)\r= 0.9(Bq)\r“c 4 = 9 / 6 0 ( B q ) , ¿À õ = 4 " i° 639÷øÁÜ·\r= ^ Z ^ - ln 6 = 1 .5 x l0 4 (a )\r--------- In -\r0.693 A 0.693.\r17T 4 f ù - . ' ú q 1.5ü0 "\rÿ  0@P\r` p ? 3 9 È1C)26W , ??`p0@\r??\r\r !"#$%('()'(*) P,-./\r41H f 1He + 2 /e + 2Vc+2y + 24.67MeV\r>?0@P?@./\r1 5x1030\rW = --------x6.02xl023 x24.67xl06 xl.6x10 19 = 8.91xl044 (J)\r4x10-3\rKL`p0@M?>.\rW 8 91 x 1 044\rN = O O= - ------ O =2.285 xlO18 (s) =7.25x101° (a)\rP 3.9xl 026 - J