c=%d\nn , a, b, c) .\r)\r4 5 . ;?firnÓf/ÔÇ?]a fÕÖ×r y /Q·0\r½×XRØÙÚQ·/;ÛrR½Ür y /Q·RØ\rÙ 0 ; fÝAa fÕ/a [l]X a[n]Ra[0]Q·`pÞ ß\rÜàáQJÑ6J\rfun(int a[],int y,int n)\r{int k=0;\ra[0]=y;k=n;\rwhile( k>2 ) kC;\rreturn(if(a[O]==a[k-l] k; else 0 ); Smâ¬\r?Rµã %ä<0\n¼åÇÇæ?0ä0{}\r?éã<0\r)\r46= /*;Ý"#/ÔÇ? ëìFibonaccif Ý ¬ 1 0 Y\rR1,1,2,3,5,8íJÑî"#/ïðRñæ?òî¤/"\r#RÌ"#stJ('~¯?
ïð 3 ?3v¾R5\r3x¾J) * / ~143\r#include <stdio.h>\rvoid main().\rlong sum=0,a[30]={l,l>2};\rint k;\rfor( k=2;k<10;k++)\ra[k] = a[k-l]+a[k-2];\rfor( k=l;k<=10;k++)\rsum += a[k-l]; d ¯?0óôïðmÇî¬\r?@P/i r\rprintf(H %ld\nH,sum);
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