r) ÍÎc225?+¢ÍÎc75?.\r40. 5 =& Õ¬Ö×_?601ا?ÙÚÛÜÝ®¼Þß+àáâ¼b£ãä.\r1 åæçZãä}\n =j+èaéZãäà8\rjê.\r2 601Ø O ÚÙ\n?{ëjA ÚÙ\n?{ëj =ì?\rP1 21 42%=50 ë&\r144-50=28%\r50X24%= 12 ë&\ríb<\r(2) (21 - 14) 4-14\r=74-14\r=0.5\r4 2 1 5 6 2 2 5.\r= 5 0 %\r : 601Ø ?ÚÙ\n?{ëjA ÚÙ\n?{ëj50%.\r41. 5 =&>\r+\n¡¢£«\nÈï/ð\n6.5cm, ¡ó£«\rÈï/ð5.5cm.ô±õö+ ¡¢£«\nÈï/ð\n195km,\r¡ó£«\nÈï/ð\nªM. 3P&\rP 95km= 19500000cm\r6.5 19500000cm=5.5 x\r6.5x= 19500000X5.5\rx = 16500000\r16500000·M= 1 6 5 ªM\r)¢¡ó£«\n165ªM.\r42. 5 =&>?CDK1.2?2\n¸¹ø+½ ù 15a”+Åû>üýþÄèÿ 0@\rP`p?18c%\r??\r1.2 != 120 \r120X &18- 15 \r= 120X3\r=360 & \r+??360\r, 2 2 - . 2 2 -