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高中化学方程式总结

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2(g)=8CO2(g)+9H2O(1)Ni(g)+O2(g)=NC>2(g)AH=+180.7kJ,mol-1\rÊH=-5518kJPmol-1ÐÑÒ\rNX(g)+3H2(g)-2NH3(g);ÊH=-92.4kJ-mol\r3ÓÔrÓÕ\rCH30HË+Oz(g)C02(g)+2HzO(l)ÐÑÒ\r4NH3(g)+5O2(g)=~=4N0(g)+6H2O(g)AH=\rAH=-725.8kJPmol-1\r-907kJ,mol1\rC2H50HË+3O2(g)=2CO2(g)+3H2O(1)1\r12N0(g)+O2(g)=2NO2(g)ÊH=-113kJPmol-\rAH=-1367kJPmol-EvaluationWarning:ThedocumentwascreatedwithSpire.PDFfor.NET.\r3NO2(g)+H2O(1)=2HNO3(1)+NO(g)AH=-136kJinol".\rN2H4(g)+O2(g)=N2(g)+2H2O(g)AH=-534kJ-mor1\rN2H4(1)+2H2O2(1)=N2(g)+4H2O(g);\rÊH=-641.6kJ*mor1\r2N2H4(g)+2NO?(g)=3N2(g)+4H2O(g)\rÊH=-1135.7kJ*mol1.\rP\rP4(×ØXs)=4P(_ØXs)ÊH=-66.8kJ*mol”.\rs٘\rS(g)+O2(g)====SO2(g);ÊH=-297kJ*mol'1\rIjÚÛ1\rFeS2(s)+eO2(g)====eFe2()3(s)+2SCh(g);\rÊH=-853kJ*mol"\r1ÐÑÒ\rSCh(g)+5'2(g)ÜeSO3(g);ÊH=Ý98.3kJ*mol-\rSO3(g)+H2O(1)=H2so4ËAH=-130.3kJ*mol”

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