(OH)48H2OêJDM @ABC@4NaB(OH)\r4+2CO2+3H2O=Na2B4O5(OH)4'8H2O1+2NaHCO3\r=>?4NaB(OH)4+2CO2+3H2O=Na2B4O5(OH)4'8H2O?+2NaHCO3\r(3)H3BO3ë°±Çp×¢ÀdÁ°±%cÂ?ÃÄ £QLJJ@pLJ$% ªÆ¦ì[o \r¶¦°±Çm\r=>?¢ÀdÁ°±%cÂ?ÃÄ £QLJJ@pLJ$% ªÆ¦ì[o ¶¦°±Ç\r(4)£íîïp[o@$%?Æ(b@ð&( ñò-óôhõ(m\r=>?$%?Æ(b@ð&( ñò-óôhõ(\rH3BO30NaOH\rImolImol\rn(H3BO3)0.2000mol/LX22.00X103L\rwn(H3BO3)=0.0044mol\rm(H3BO3)=n(H3BO3)xM(H3BO3)=0.0044niolx62g/mol=0.2728g\r0.2728g\röz@xl00%=90.9%\r0.3g\r(5)M÷DEGHWøHP`E DGHùgaúÉR^û÷ aú@üGHýþúm·ÿB(OH)4-0@b\rP`p?\nM`p?H+\r??H3BO3,bPPNa+@cP`pNcP\rPN??!"#$%&'(\r)*+,-./0bPP1H++B(OH)4XH3BO3+H2O,1234Imol??ImolH3BO3;\r5678\r1mole-1/402(M)0ImolH3BO301/2:(N)\r;<+=??ImolfhBCh,>?@??(1/2+1/4)molX22.4L/mol=16.8LA(CDEF)\rG*+,-./0N`HI:HNaOHKL?"#Ma%<b%\rNOM16.8<