高考化学二轮复习 压轴题热点练2 盖斯定律的应用-人教版高三全册化学

①②③,根据盖斯定律,由③-①-②可得\rSO(g)+MnO(s)===MnSO(s)ΔH=(-1065kJ·mol-1)-(-520kJ·mol-1)-(-297\r224\rkJ·mol-1)=-248kJ·mol-1。\r8.已知下列热化学方程式:\r①FeO(s)+3CO(g)===2Fe(s)+3CO(g)ΔH=-25kJ·mol-1\r232\r②3FeO(s)+CO(g)===2FeO(s)+CO(g)ΔH=-47kJ·mol-1\r23342\r.专业.\r.\r③FeO(s)+CO(g)===3FeO(s)+CO(g)ΔH=+19kJ·mol-1\r342\r写出FeO(s)被CO还原成Fe和CO的热化学方程式______________。\r2\r答案FeO(s)+CO(g)===Fe(s)+CO(g)ΔH=-11kJ·mol-1\r2\r解析①×3-②-③×2就可得6FeO(s)+6CO(g)===6Fe(s)+6CO(g)ΔH=-66\r2\rkJ·mol-1,\r即FeO(s)+CO(g)===Fe(s)+CO(g)ΔH=-11kJ·mol-1。\r2\r9.已知:①2CuS(s)+3O(g)===2CuO(s)+2SO(g)ΔH=-768.2kJ·mol-1\r2222\r②2CuO(s)+CuS(s)===6Cu(s)+SO(g)ΔH=+116.0kJ·mol-1\r222\r则CuS(s)+O(g)===2Cu(s)+SO(g)ΔH=____________________。\r222\r答案-217.4kJ·mol-1\r1\r解析根据盖斯定律,将方程式×(①+②)得CuS(s)+O(g)===2Cu(s)+SO(g)ΔH\r3222\r1\r=×(-768.2+116.0)kJ·mol-1=-217.4kJ·mol-1。\r3\r.专业.