毕业设计（论文）-三效蒸发制碱装置设计

蒸发水量则:ws11=228001+1.1+1.2=6909Kghws12=228001+1.1+1.2*1.1=7600Kghws13=228001+1.1+1.2*1.2=8291Kgh2.3选取各效出效浓度加斯那个一效出效浓度为12.3%从手册中查得100℃时12.3%NaoH水溶液中:含NaoH:18.2%、水:69.5%则:ws1=5[1000xa·xw-1000xa1·xw1+5001+1.1+1.2]=5[10000.1*0.72-10000.123*0.695+5003.3]=8505.5Kgh因ws1近似等于ws11故xa1=12.3%xw1=69.5%xs1=18.2%假定二效出效浓度为17.2%,从手册中查得100℃时,在17.2%NaoH水溶液中含Nacl14.6%水68.2%则ws2=5[1000xa1·xw1-1000xa2·xw2+5001+1.1+1.2*1.1]=5[10000.123·0.695-10000.172·0.682+5001+1.1+1.2*1.1]=9260Kgh因ws2=ws22故:xa2=17.2%xw2=68.2%xs2=14.6%所以,第三效蒸发水量ws3=ws-ws1-ws2=22800-8505.5-9260=5034.5Kgh所以各效碱溶液浓度分布为:NaoHNacl水Ⅰ效进料xa=10%xs=18%xw=72%Ⅰ出料Ⅱ进料xa1=12.3%xs1=18.2%xw1=69.5%Ⅱ效Ⅱ出料Ⅲ进料xa2=17.2%xs2=14.6%xw2=68.2%Ⅲ效出料xa3=30%xs35.8%xw3=64.2%2.4物料平衡计算1、Ⅰ效的物料计算A、进料量G=4000xa=40000KghB、进入淡水量:Gc1=500*5=2500KghC、蒸发水量:ws1=G+25003.3=40000=6958kg/hD、析出盐量: