40米扣件式脚手架计算书

01kN·mσ=N/(φA)+Mw/W=17892.53/(0.265×450)+9610.65/4730=152.07N/mm2≤[f]=205N/mm2满足要求!八、脚手架搭设高度验算不组合风荷载作用Hs1=(φAf-(1.2NG2k+1.4NQ1k))×H/(1.2NG1k)=(0.265×450×205×10-3-(1.2×6.4+1.4×2.16))×40/(1.2×6.25)=73.37m组合风荷载作用Hs2=(φAf-(1.2NG2k+0.9×1.4×(NQ1k+MwkφA/W)))×H/(1.2NG1k)=(φAf-(1.2NG2k+0.9×1.4×NQ1k+MwφA/W))×H/(1.2NG1k)=(0.265×450×205×10-3-(1.2×6.4+0.9×1.4×2.16+0.01×1000×0.265×450/4730))×40/(1.2×6.25)=73.68mHs=73.37m>H=40m满足要求!九、连墙件承载力验算连墙件布置方式两步三跨连墙件连接方式扣件连接连墙件约束脚手架平面外变形轴向力N0(kN)3连墙件计算长度l0(mm)600连墙件截面面积Ac(mm2)489连墙件截面回转半径i(mm)158连墙件抗压强度设计值[f](N/mm2)205连墙件与扣件连接方式单扣件扣件抗滑移折减系数0.95Nlw=1.4×ωk×2×h×3×la=1.4×0.04×2×1.5×3×1.25=0.57kN长细比λ=l0/i=600/158=3.8,查《规范》表A.0.6得,φ=0.99(Nlw+N0)/(φAc)=(0.57+3)×103/(0.99×489)=7.36N/mm2≤0.85×[f]=0.85×205N/mm2=174.25N/mm2满足要求!扣件抗滑承载力验算:Nlw+N0=0.57+3=3.57kN≤0.95×8=7.6kN满足要求!