200×500梁模板(120板)计算书

×(1+2)×0.95]×(0.95/2+(0.6-0.2/2)/2)Р+1.35×0.15×2.97=11.856kNР R2=5.459+[1.2×(0.5+(24+1.1)×0.12)×0.95+1.4×(1+2)×0.95]×(0.95/2+(1.2-0.6-0.2/2)/2)Р+1.35×0.15×2.97=11.856kNР Nut=max[R1,R2]=max[11.856, 11.856]=11.856kNР 1.05Nut/(φAKH)=1.05×11.856×103/(0.218×424×1)=134.677N/mm2≤[f]=205N/mm2Р 符合要求!Р 2) 组合风荷载时立杆从左到右受力为(Nut=γG∑NGk+0.85×1.4∑NQk):Р R1=11.165kN, R2=11.165kNР Nut=max[R1,R2]=max[11.165, 11.165]=11.165kNР Mw=0.85×1.4ωk lah2/10=0.85×1.4×0.114×0.95×1.82/10=0.042kN·mР 1.05Nut/(φAKH)+Mw/W=Р1.05×11.165×103/(0.218×424×1)+0.042×106/(4.49×103)=136.136N/mm2≤[f]=205N/mm2Р 符合要求!Р 4、整体侧向力验算Р结构模板纵向挡风面积AF(m2)Р15Р F=0.85AFωkla/La=0.85×15×0.315×0.95/30=0.127kNР N1=3FH/[(m+1)Lb]=3×0.127×2.97/[(14+1)×15]=0.005kNР σ=(1.05Nut+N1)/(φAKH)=Р(1.05×11.165+0.005)×103/(0.218×424×1)=126.888N/mm2≤[f]=205N/mm2Р 符合要求!