Kim=1.85,则:Р冲击电流ich = 1.414KimI’2 =1.414×1.85×9.12=23.86(kA)Р短路容量:Sk’2 = ·I·Uk2 =×9.12×37.5 = 592.34(MVA)Р Sk”2 = ·I·Uk2 =×4.51×37.5 = 292.92(MVA)Р当K3点短路时简化等值网络图如下:РX20Р?X5 K3 X22 X23 K3 X22РX21РX20 = X1+X2+X3+X4 = 0.691РX21 = X6+X7//X8//X9//X10//X11 = 0.136РX22 = 0.126РX23 = X20//X21+X5 = 0.288РXf = X23//X22 = 0.088Р查运算曲线得:Рt=0s时,I’3* = 8.963 t=4s时,I”3* = 2.512РI’3 = I’3* ×(SN/1.732Uav) = 8.963×(93.75/1.732×10.5) = 46.2(kA)РI”3 = I”3* ×(SN/1.732Uav) = 2.512×(93.75/1.732×10.5) = 12.95(kA)Р取冲击系数Kim=1.85,则:Р冲击电流ich = 1.414KimI’3 =1.414×1.85×46.2=101.4(kA)Р短路容量:Sk’3 = ·I·Uk3 =×46.2×10.5 = 840.19(MVA)Р Sk”3 = ·I·Uk3 =×12.95×10.5 = 235.51(MVA)Р1.4 短路电流计算结果表Р短路点编号Р基准电压Р短路电流(kA)Р冲击电流(kA)Р短路容量(MVA)Рt=0Рt=4sРK1Р115Р2.49Р1.51Р6.51Р495.96РK2Р37.5Р9.12Р5.51Р23.86Р592.34РK3Р10.5Р46.2Р12.95Р101.4Р840.19
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