采面供电设计

∑ X=X X +X g /K b 2 +X b =0.0288+0.1092/5 2 +0.1072=0.140368 I d1 =Ue/2??? 22XR =1200/2 22104368 .0046428 .0?=4058A 2、采煤机 1)采煤机短路电流计算 MCP50mm 2L=0.120KM R=0.491*0.120=0.05892 X=0.081*0.12=0.00972 ∑R=0.046428+0.05892=0.105348 ∑X=0.140368+0.00972=0.150088 I d2=Ue/2??? 22XR =3108.5A 采煤机开关的整定计算 Pe=300KW Ue=1200V Ie=182A (1) 过流保护: Iz=182A (2)短路保护 I d=8* Iz=1456A (3)灵敏度系数效验 I d2/8Iz=3108/1456=2.13>1.2 满足灵敏度的要求( 4)根据开关特性,过负荷整定为: 182A 短路整定为 6Iz 3、转载机 1)转载机短路电流计算电缆截面: MYP 25mm 2L=0.15KM R=0.937*0.15=0.14055 X=0.088*0.15=0.0132 ∑R=0.046428+0.14055=0.186978 ∑X=0.140368+0.01408=0.153568 I d3=Ue/2??? 22XR =2479.8A 转载机开关的整定: Pe=110KW Ue=660V Ie=66A (1) 过流保护: Iz=66A (2)短路保护 I d3=8* Iz=528A (3)灵敏度系数效验 I d/8Iz=2479.8/528=4.69>1.2 满足灵敏度的要求( 4)根据开关特性,过负荷整定为: 66A 短路整定为 6Iz 4、乳化液泵 1)乳化液泵短路电流计算电缆截面: MYP 25mm 2